Tag: 570 Managers with at Least 5 Direct Reports

  • Leetcode SQL: 570 Managers with at Least 5 Direct Reports

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    SELECT e.name FROM Employee e JOIN ( SELECT managerId FROM Employee WHERE managerId IS NOT NULL GROUP BY managerId HAVING COUNT(*) >= 5 ) AS ManagersWithReports ON e.id = ManagersWithReports.managerId; Explanation: Subquery – Find Managers with at Least 5 Reports: We first create a subquery to count how many direct…