Leetcode SQL: 378. Replace Employee ID With The Unique Identifier

SQL Code:

SELECT eu.unique_id, [name]
FROM Employees e WITH (NOLOCK)
LEFT OUTER JOIN EmployeeUNI eu WITH (NOLOCK) ON e.id = eu.id;

Explanation:

  1. SELECT eu.unique_id, [name]:
    This line specifies that we want to retrieve the unique_id from the EmployeeUNI table and the name from the Employees table.

    • eu.unique_id: Represents the unique identifier for the employee from the EmployeeUNI table.
    • [name]: Represents the employee’s name from the Employees table.

    这一行指定了我们要从 EmployeeUNI 表中获取 unique_id,以及从 Employees 表中获取 name

    • eu.unique_id: 表示来自 EmployeeUNI 表的员工唯一标识符。
    • [name]: 表示来自 Employees 表的员工姓名。
  2. FROM Employees e WITH (NOLOCK):
    The FROM clause specifies that we are selecting data from the Employees table and aliasing it as e. The WITH (NOLOCK) table hint allows the query to read the data without placing shared locks on the Employees table. This can improve query performance, particularly in high-concurrency environments, but it may result in reading uncommitted or dirty data.

    FROM 子句指定我们正在从 Employees 表中选择数据,并将其别名为 eWITH (NOLOCK) 表提示允许查询在不锁定 Employees 表的情况下读取数据。这可以提高高并发环境下的查询性能,但可能导致读取未提交或脏数据。

  3. LEFT OUTER JOIN EmployeeUNI eu WITH (NOLOCK) ON e.id = eu.id:
    The LEFT OUTER JOIN joins the Employees table (e) with the EmployeeUNI table (eu) on the condition that the id in the Employees table matches the id in the EmployeeUNI table.

    • If an employee exists in the Employees table but does not have a matching entry in the EmployeeUNI table, the result will still include the employee’s name, but the unique_id will be NULL.

    LEFT OUTER JOINEmployees 表 (e) 与 EmployeeUNI 表 (eu) 连接,条件是 Employees 表中的 idEmployeeUNI 表中的 id 匹配。

    • 如果 Employees 表中的员工没有在 EmployeeUNI 表中找到匹配的条目,结果仍然会包含该员工的姓名,但 unique_id 将会是 NULL

Key Concepts:

  • LEFT OUTER JOIN:
    A LEFT OUTER JOIN ensures that all records from the left table (Employees) are included in the result, even if there is no matching record in the right table (EmployeeUNI). If no match is found, the unique_id will return as NULL.

    LEFT OUTER JOIN:
    LEFT OUTER JOIN 确保左表(Employees)中的所有记录都会包含在结果中,即使在右表(EmployeeUNI)中没有匹配的记录。如果没有找到匹配项,unique_id 将会是 NULL

  • NOLOCK:
    The WITH (NOLOCK) hint improves performance by allowing the query to read data without locking the table. However, it can result in reading uncommitted or dirty data, so use it cautiously in environments where data consistency is important.

    NOLOCK:
    WITH (NOLOCK) 提示通过允许查询在不锁定表的情况下读取数据来提高性能。然而,它可能会导致读取未提交或脏数据,因此在数据一致性很重要的环境中应谨慎使用。

Warnings:

  • Reading Dirty Data:
    Using WITH (NOLOCK) can result in reading uncommitted or dirty data, which may not reflect the actual state of the database. In production systems where data accuracy is critical, avoid using NOLOCK.

    读取脏数据:
    使用 WITH (NOLOCK) 可能会导致读取未提交或脏数据,这可能无法反映数据库的实际状态。在数据准确性至关重要的生产系统中,避免使用 NOLOCK

Summary:

This query retrieves the unique_id from the EmployeeUNI table and the name from the Employees table. It uses a LEFT OUTER JOIN to include all employees, even if they do not have a corresponding unique identifier. The WITH (NOLOCK) hint is used to improve performance by avoiding table locks, but be cautious of the potential for dirty reads.

中文总结:
该查询从 EmployeeUNI 表中检索 unique_id,并从 Employees 表中检索 name。它使用 LEFT OUTER JOIN 来包含所有员工,即使他们没有对应的唯一标识符。WITH (NOLOCK) 提示用于提高性能,避免锁表,但需要注意可能出现脏读的风险。

Tips:

  • When to Use LEFT OUTER JOIN:
    Use LEFT OUTER JOIN when you need to include all records from the left table, regardless of whether there is a match in the right table.

    何时使用 LEFT OUTER JOIN:
    当需要包含左表中的所有记录,而不管右表中是否有匹配时,使用 LEFT OUTER JOIN

  • Optimizing Performance:
    Ensure that there are indexes on the id column in both tables (Employees and EmployeeUNI) to optimize the performance of the JOIN operation.

    优化性能:
    确保在两个表的 id 列上创建索引(EmployeesEmployeeUNI),以优化 JOIN 操作的性能。

Similar SQL Problems:

  1. LeetCode 176: Second Highest Salary
    This problem involves retrieving specific data from a table and handling conditions similar to how we retrieve the unique identifier here.

  2. LeetCode 181: Employees Earning More Than Their Managers
    This problem also involves joining tables to retrieve data based on specific conditions, similar to how we use JOIN here.

  3. LeetCode 183: Customers Who Never Order
    Similar to how we use LEFT OUTER JOIN here to include all employees, this problem involves filtering customers based on whether they placed an order.

  4. LeetCode 196: Delete Duplicate Emails
    This problem focuses on identifying and filtering rows based on specific conditions, similar to how we retrieve and match employee data.

  5. LeetCode 184: Department Highest Salary
    This problem filters rows based on specific conditions, which is aligned with how we use JOIN to filter employee data.


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